3m^2-605=0

Solution for 3m^2-605=0 equation:

3m^2-605=0

a = 3; b = 0; c = -605;
Δ = b2-4ac
Δ = 02-4·3·(-605)
Δ = 7260
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7260}=\sqrt{484*15}=\sqrt{484}*\sqrt{15}=22\sqrt{15}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-22\sqrt{15}}{2*3}=\frac{0-22\sqrt{15}}{6}
=-\frac{22\sqrt{15}}{6}
=-\frac{11\sqrt{15}}{3}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+22\sqrt{15}}{2*3}=\frac{0+22\sqrt{15}}{6}
=\frac{22\sqrt{15}}{6}
=\frac{11\sqrt{15}}{3}
$